05/31/2020 (2011: National Sprint Round, Problem 2)

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Q: A local restaurant boasts that they have 240 different dinner combinations. A dinner combination consists of an appetizer, entrée, and dessert. If the restaurant offers 10 appetizer choices and 6 entrée choices, how many different dessert choices does it have?


A: 4
Total Dinner Combinations = Appetizer ⋅ Entrée ⋅ Dessert -->
240 = 10 ⋅ 6 ⋅ Dessert -->
240 = 60 ⋅ Dessert -->
240 ÷ 60 = Dessert -->
4 = Dessert

Comments

  1. AnonymousJune 2, 2020 at 1:32 PM

    Your explanation for this math problem is great. I really like the way you show how to solve the problems. Keep up the great work!

    ReplyDelete

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